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'use strict' /* * Method * * Methods are added, conceptually, to Genfuns, not to objects * themselves, although the Genfun object does not have any pointers to * method objects. * * The _rank vector is an internal datastructure used during dispatch * to figure out whether a method is applicable, and if so, how to * order multiple discovered methods. * * Right now, the score method on Method does not take into account any * ordering, and all arguments to a method are ranked equally for the * sake of ordering. * */ const Role = require('./role') const util = require('./util') module.exports = Method function Method (genfun, selector, func) { var method = this method.genfun = genfun method.func = func method._rank = [] method.minimalSelector = 0 const tmpSelector = selector.length ? selector : [Object.prototype] for (var object, i = tmpSelector.length - 1; i >= 0; i--) { object = Object.hasOwnProperty.call(tmpSelector, i) ? tmpSelector[i] : Object.prototype object = util.dispatchableObject(object) if ( typeof object === 'function' && !object.isGenfun ) { object = object.prototype } if (i > 0 && !method.minimalSelector && util.isObjectProto(object)) { continue } else { method.minimalSelector++ if (!Object.hasOwnProperty.call(object, Role.roleKeyName)) { // Object.defineProperty is JS 1.8.0+ Object.defineProperty( object, Role.roleKeyName, {value: [], enumerable: false}) } // XXX HACK - no method replacement now, so we just shove // it in a place where it'll always show up first. This // would probably seriously break method combination if we // had it. object[Role.roleKeyName].unshift(new Role(method, i)) } } } Method.setRankHierarchyPosition = (method, index, hierarchyPosition) => { method._rank[index] = hierarchyPosition } Method.clearRank = method => { method._rank = [] } Method.isFullySpecified = method => { for (var i = 0; i < method.minimalSelector; i++) { if (!method._rank.hasOwnProperty(i)) { return false } } return true } Method.score = method => { // TODO - this makes all items in the list equal return method._rank.reduce((a, b) => a + b, 0) }